In Young's double slit experiment, the slits are 0.5 mm apart and interference pattern is observed on a screen placed at a distance of 1.0 m from the plane containing the slits. If wavelength of the incident light is 6000 Å, then the separation between the third bright fringe and the central maxima is
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a
4.0 mm
b
3.5 mm
c
3.0 mm
d
2.5 mm
answer is B.
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Detailed Solution
Separation nth bright fringe and central maxima is xn=nλDd So, x3=3×6000×10−10×10.5×10−3=3.5mm
In Young's double slit experiment, the slits are 0.5 mm apart and interference pattern is observed on a screen placed at a distance of 1.0 m from the plane containing the slits. If wavelength of the incident light is 6000 Å, then the separation between the third bright fringe and the central maxima is