First slide

Coherent sources and their importance in interference

Question

In Young's double slit experiment, the slits are 0.5 mm apart and interference pattern is observed on a screen placed at a distance of 1.0 m from the plane containing the slits. If wavelength of the incident light is 6000 Å, then the separation between the third bright fringe and the central maxima is

Easy

A

4.0 mm
B

3.5 mm
C

3.0 mm
D

2.5 mm

Solution

$Separation n^{th} bright fringe and central maxima is x_{n} = \frac{nλD}{d} So, x_{3} = \frac{3 \times 6000 \times 10^{- 10} \times 1}{0 .5 \times 10^{- 3}} = 3 .5 mm$

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