In Young's double slit experiment, the 8th maximum with wavelength${\mathrm{\lambda }}_1$ is at a distance d₁  from central  maximum.and 6 th maximum with wavelength ${\lambda }_2$ is at   a distance d₂ .then d₁/ d₂  is 

• A

  $\frac{4}{3}\left(\frac{{\mathrm{\lambda }}_2}{{\mathrm{\lambda }}_1}\right)$

• B

  $\frac{4}{3}\left(\frac{{\mathrm{\lambda }}_1}{{\mathrm{\lambda }}_2}\right)$

• C

  $\frac{3}{4}\left(\frac{{\mathrm{\lambda }}_2}{{\mathrm{\lambda }}_1}\right)$

• D

  $\frac{3}{4}\left(\frac{{\mathrm{\lambda }}_1}{{\mathrm{\lambda }}_2}\right)$