In Young's double slit experiment, the 8th maximum with wavelength ${\lambda }_1$ is at a distance d₁ from the central maximum and the 6th maximum with a wavelength ${\lambda }_2$ is at a distance d₂. Then (d₁/d₂) is equal to

• A

  $\frac{4}{3}\left(\frac{{\lambda }_2}{{\lambda }_1}\right)$

• B

  $\frac{4}{3}\left(\frac{{\lambda }_1}{{\lambda }_2}\right)$

• C

  $\frac{3}{4}\left(\frac{{\lambda }_2}{{\lambda }_1}\right)$

• D

  $\frac{3}{4}\left(\frac{{\lambda }_1}{{\lambda }_2}\right)$