In Young's double slit experiment, the two slits act as coherent sources of equal amplitude A and of wavelength λ in another experiment with the same set up, the two slits are sources of equal amplitude A and wavelength λ but are incoherent. The ratio of the intensity of light at the midpoint of the screen in the first case of that in the second case is
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a
1:1
b
1:2
c
2:1
d
2 :2
answer is C.
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Detailed Solution
when the tow sources are coherent. then amplitude at mid-point = A+ A = 2A I1∝(2A)2 or I1=k×4A2 When the two sources are incoherent, thenI2∝A2+A2 or I2=k×2A2 I1I2=k×4A2k×2A2=2