In a Young’s double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be:

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1 mm

0.25 mm

0.75 mm

0.50 mm

answer is B.

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Detailed Solution

in YDSE fringe width β=Dλd⇒β=1×500×10−92×10−3=250×10-6m=0.25mm

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