In Young’s double slit experiment, we get 60 fringes in the field of view of monochromatic light of wavelength 4000 A0. If we use monochromatic light of wavelength 6000 A0, then the number of fringes that would be visible
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a
60
b
90
c
40
d
75
answer is C.
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Detailed Solution
n1β1=n2β2 as the length of the region is samen1λ1=n2λ260×4000=n26000n2=40