First slide

Coherent sources and their importance in interference

Question

In Young's double slit experiment when wavelength used is 6000 Å and the screen is 40 cm from the slits, the fringes are 0.012 cm wide. What is the distance between the slits

Easy

A

0.024 cm
B

2.4 cm
C

0.24 cm
D

0.2 cm

Solution

$β = \frac{λD}{d} \Rightarrow d = \frac{λD}{β} = \frac{6000 \times 10^{- 10} \times (40 \times 10^{- 2})}{0 .012 \times 10^{- 2}} = 0 .2 cm$

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