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Q.

In Young's double slit experiment with a monochromatic light of wavelength 4000 A0  , the fringe width is found to be 0.4  mm . When the slits are now illuminated with a light of wavelength 5000 A0  the fringe width will be

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a

0.32 mm

b

0.5 mm

c

0.6 mm

d

0.8 mm

answer is B.

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Detailed Solution

The given values areλ1=4000A0,   λ2=5000A0β1=0.4×10−3m , β2=?Fringe width β=λDd                      β1β2=λ1λ2 ( β ∞ λ )                  ∴β2=β1λ2λ1                   β2=0.4×10−3×50004000                ∴ β2=0.5 mm
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