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In the Young’s double slit experiment with sodium light. The slits are 0.589 m a part. The angular separation of the third maximum from the central maximum will be (given λ = 589 mm)

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a

sin−1⁡0.33×108

b

sin−1⁡0.33×10−6

c

sin−1⁡3×10−8

d

sin−1⁡3×10−6

answer is D.

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Detailed Solution

Using relation, dsin⁡θ=nλ⇒sin⁡θ=nλd For n=3,sin⁡θ=3λd=3×589×10−90.589 =3×10−6 or θ=sin−1⁡3×10−6

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In the Young’s double slit experiment with sodium light. The slits are 0.589 m a part. The angular separation of the third maximum from the central maximum will be (given λ = 589 mm)