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Q.

In the Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is λ is K, (λ being the wave length of light used). The intensity at a point where the path difference is λ/4, will be :

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a

K

b

K/4

c

K/2

d

Zero

answer is C.

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Detailed Solution

For path difference, λ, phase difference = 2π radFor path difference λ4, phase difference = π2 radAs K = 4I0. So, intensity at given point where path difference is λ4K′=4I0cos2⁡π4=2I0=K2
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