In Young’s double–slit experiment the separation between the slits is doubled and the distance between the slit and the screen is halved. The fringe–width becomes
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a
One–fourth
b
Half
c
Double
d
Quadruple
answer is A.
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Detailed Solution
Distance between the two slits d'=2d Distance between the slit and the screen D'=D2 Fringe width β=λDd and β'=λD'd' =λ(D/2)2d =λD4d ∴ β'=β4