First slide

Young's double slit Experiment

Question

In a Young’s experiment the fringes are displaced by a distance ‘x’ when a glass plate of refractive index 1.5 is introduced in the path of one of the beam. When this plate is replaced by another plate of same thickness, then the displacement of fringes is $(\frac{3}{2} x)$ . The refractive index of second plate is

Moderate

A

1.75
B

1.50
C

1.25
D

1.00

Solution

$S = \frac{D}{d} (μ - 1) t$
$x = \frac{D}{d} (1.5 - 1) t - - - (1)$
$\frac{3 x}{2} = \frac{D}{d} (μ - 1) t$

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