The Young's experiment is performed with the lights of blue ($\mathrm{\lambda }$ = 4360 Å) and green colour ($\mathrm{\lambda }$ = 5460 Å), If the distance of the 4th fringe from the centre is x, then

• A

  $\mathrm{x}\text{ (Blue) }=\mathrm{x}\text{ (Green) }$

• B

  $\mathrm{x}\text{ (Blue)> }\mathrm{x}\text{ (Green) }$

• C

  $\mathrm{x}\text{ (Blue) }<\mathrm{x}\text{ (Green) }$

• D

  $\frac{\mathrm{x}\left(\text{ Blue }\right)}{\mathrm{x}\left(\text{ Green }\right)}=\frac{5460}{4360}$