The Young's experiment is performed with the lights of blue (λ = 4360 Å) and green colour (λ = 5460 Å), If the distance of the 4th fringe from the centre is x, then
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a
x (Blue) =x (Green)
b
x (Blue)> x (Green)
c
x (Blue)
d
x( Blue )x( Green )=54604360
answer is C.
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Detailed Solution
Distance of nth bright fringe yn=nλDd i.e. yn∝λ n=4 for both colours ∴yn1yn2=λ1λ2⇒x (Blue) x (Green ) =43605460 ∴x (Green) >x (Blue).