The Young's experiment is performed with the lights of blue $(\lambda =4360\text{Å})$ and green colour $(\lambda =5460\text{Å})$.  If the distance of the 4th fringe from the centre is x, then 

• A

  $x\left(\text{ Blue }\right)=x\text{ (Green) }$

• B

  $x\text{ (Blue) }>x\text{ (Green) }$

• C

  $x\text{ (Blue) }<x\text{ (Green) }$

• D

  $\frac{x\left(\text{ Blue }\right)}{x\left(\text{ Green }\right)}=\frac{5460}{4360}$