The Young's experiment is performed with the lights of blue (λ = 4360 Å) and green colour (λ= 5460 Å), If the distance of the 4th fringe from the centre is x, then
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a
x (Blue) = x (Green)
b
x (Blue)> x (Green)
c
x (Blue) < x (Green)
d
x(Blue)x(Green)=54604360
answer is C.
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Detailed Solution
Distance of nth bright fringe yn=nλDdi.e. yn∝λ ∴xn1xn2=λ1λ2 ⇒x(Blue)x(Green)=43605460∴x (Green) > x (Blue).