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Q.

The youngs modulus of the material of a rod is 20×1010 pascal. When the longitudinal strain is 0.04%, The energy stored per unit volume is

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a

4×10−3J/m3

b

8×103J/m3

c

16×10−3J/m3

d

16×103J/m3

answer is D.

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Detailed Solution

y=20×1010N/m2;Δℓℓ=0.04100=4×10−4 WV=12Y( strain )2=12×20×1010×16×10−8 =16×103J/m3
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