The Young's modulus of a rope of 10m length and having diameter of 2 cm is 20×1011dyne cm-2.If the elongation produced in the rope is 1 cm, the force applied on the rope is

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6.28×105N

6.28×104N

6.28×104 dyne

6.28×105 dyne

answer is B.

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Detailed Solution

Young's modulus of a rope, Y=FLAΔlGiven, L=10m,A=πr2=π(1)2=πY=20×1011 dyne cm−2,Δl=1cm ⇒F=Y⋅A⋅ΔlL⇒F=20×1011×π×110×102 F=6.28×109 dyne or F=6.28×104N

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