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Q.

Young's modulus of rubber is 104 N/m2 and area of cross section is 2 cm2 . If force of 2 x 105 dyn is applied along its length ,  length increases by 1m, then its initial length l becomes

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a

3l

b

4l

c

2l

d

None of these

answer is C.

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Detailed Solution

Δl=FlaY1=2×105×10−5×L2×10−4×104  or  L=1mSo, INITIAL  length is 1 m
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Young's modulus of rubber is 104 N/m2 and area of cross section is 2 cm2 . If force of 2 x 105 dyn is applied along its length ,  length increases by 1m, then its initial length l becomes