Q.
Young's modulus of steel is 19×1010N/m2 . Express it as x×1011 dyne /cm2. Here dyne is the CGS unit of force. The value of x is ________________
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 19.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
The unit of Young's modulus is N/m2. This suggests that it has dimensions of Force ( distance )2 Thus, [Y]=[F]L2=MLT−2L2=ML−1T−2⋅N/m2 is in SI units. So, 1N/m2=(1kg)(1m)−1(1s)−2 and 1dyne/cm2=(1g)(1cm)−1(1s)−2 so, 1N/m21dyne/cm2=1kg1g1m1cm−11s1s−2=1000×1100×1=10 or 1N/m2=10dyne/cm2 or 19×1010N/m2=19×1011 dyne /cm2
Watch 3-min video & get full concept clarity