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Q.

A Zener diode having breakdown voltage equal to 25V is used in a voltage regulator circuit shown in figure. The current through the diode is

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a

5mA

b

9 mA

c

15mA

d

25 mA

answer is B.

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Detailed Solution

The voltage drop across 1kΩ=Vx=25V The current through 1kΩ=IL=251×103=25mA Voltage drop across 300Ω is 30−25=5V The current through 300Ω is I=5300=160=16mAThecurrentthroughthezenerdiodeis IZ=I-IL=25−16=9mA

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