A healthy person eats the following diet-5 gm raw sugar, 4 gm albumin, 10 gm pure buffalo  ghee adultrated  with 2 gm vegetable ghee (hydrogenated  vegetable oil) and 5 gm lignin. How many calories he is likely to get?

Carbohydrates = 5 gm (raw sugar)Proteins = 4 gm (albumin)Fats = 10 gm pure buffalo ghee + 2 gm vegetable ghee = 12 gmPhysiologic calorific value of proteins/carbohydrates = 4Physiologic calorific value of fats = 9Total Calories = (5 x 4) + (4 x 4) + (12 x 9) = 20 + 16 + 108 = 144 CaloriesNote: Lignin has no nutritive value since it cannot be digested.