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Q.

In a person, 178 litres glomerular filtrate is formed per day. If tubular reabsorption is 177 litres per day and tubular secretion is 0.25 litres per day, then the rate of urinary excretion is

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answer is 2.

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Detailed Solution

Urinary excretion = (Glomerular filtration – tubular reabsorption) + tubular secretion= 178 – 177 + 0.25 = 1.25 litres per day
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In a person, 178 litres glomerular filtrate is formed per day. If tubular reabsorption is 177 litres per day and tubular secretion is 0.25 litres per day, then the rate of urinary excretion is