Q.

The sequence given below represents flow of energy in a grassland ecosystem.      Grass→ Grasshopper→ Frog→ Snake→ Hawk If GPP is 3000 K Cal and R is 20% at the producer level, estimate the secondary productivity of snake (as per 10 percent law).

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a

2.4 K Cal

b

3.0 K Cal

c

0.24 K Cal

d

0.30 K Cal

answer is A.

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Detailed Solution

GPP = 3000 K CalR = 20% of GPP = 3000×20100=600 K CalNPP = GPP – RNPP = 3000 – 600 = 2400 K CalAs per 10 per cent law :Grass (2400 K Cal) →Grasshopper (240 K Cal)→Frog (24 K Cal)→Snake (2.4 K Cal)→Hawk (0.24 K Cal)
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