1. Find the Cartesian product A × B, where A = {1, 2} and B = {3, 4}.
Solution: A × B = {(1, 3), (1, 4), (2, 3), (2, 4)}
The RD Sharma Solutions Relations PDF for Class 11 is an essential resource for mastering the fundamental topic of relations in mathematics. This chapter introduces students to important concepts such as relation between two sets, Cartesian product, ordered pairs, and various types of relations including reflexive relation, symmetric relation, transitive relation, equivalence relation, universal relation, void relation, identity relation, and inverse relation.
Understanding these concepts is crucial for building a strong base in Relations and Functions, a key part of the CBSE syllabus relations chapter, and is frequently tested in both board and competitive exams.
Students will also learn about the representation of relations, the properties of relations, and the relation and function difference, helping them grasp the complete framework of relations in mathematics. These topics form the foundation for higher-level problem-solving and are vital for success in exams and future studies.
By using these solutions, students can easily master how to solve relations in RD Sharma for both CBSE school exams and competitive entrance tests.
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Also Check: RD Sharma Solutions Sets PDF for Class 11
Solution: A × B = {(1, 3), (1, 4), (2, 3), (2, 4)}
Solution: A × B = {(a,1), (b,1)}
Solution: R = {(1,1), (2,4), (3,9)}
Solution: Number of elements = 3² = 9.
Solution: Since (a,a) exists for each a ∈ {1,2,3}, R is reflexive.
Solution: R = A × A = {(1,1), (1,2), (2,1), (2,2)}
Solution: (2,1) ∈ R but (1,2) ∉ R, hence R is not symmetric.
Solution: Yes, R is reflexive because each element maps to itself.
Solution: Domain = {1,3,5}; Range = {2,4,6}.
Solution: (2,3) and (3,2) are present, thus R is symmetric.
Solution: R is reflexive, symmetric, and transitive. Hence, R is an equivalence relation.
Solution: Since x ≤ x for all x, R is reflexive.
Solution: Inverse relation R⁻¹ = {(2,1), (4,3), (6,5)}
Solution: Identity relation = {(1,1), (2,2), (3,3)}
Solution: Yes, a divides itself. Thus, R is reflexive.
Solution: Number of binary relations = 2^(n²) = 2⁴ = 16.
Solution: Since |a-b| = |b-a|, R is symmetric.
Solution: R = {(1,2), (1,3), (2,3)}
Solution: No extra pairs needed; thus, R is transitive.
Solution: R is reflexive but not symmetric (e.g., (a,b) exists but (b,a) doesn't).
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