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By Ankit Gupta
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Updated on 11 Jun 2025, 18:15 IST
Understanding money matters is important in our daily life. One of the most useful topics in this area is Simple Interest. This chapter in RD Sharma’s Class 7 Maths book helps students learn how to calculate the extra money earned or paid when money is borrowed or saved. Whether you want to understand how banks work or why your parents earn interest on savings, this chapter gives you the basics.
In Chapter 13 – Simple Interest, students are introduced to the idea of interest that is calculated in a simple and easy way. When you lend money to someone or deposit it in a bank, you earn extra money after some time. This extra money is called “interest.” Similarly, when you borrow money, you have to pay interest along with the money borrowed. This chapter teaches how to calculate this extra amount using a simple formula.
The Simple Interest formula is: SI = (P × R × T) / 100,
where:
The RD Sharma Solutions make it easy to understand this formula by explaining it with step-by-step methods and solved examples. These solutions are designed in a way that even a student who finds Maths difficult can follow and learn. They help students practice different types of questions that may come in school exams.
Each exercise in the chapter covers a variety of problems to build strong understanding. From direct formula-based sums to word problems involving money, time, and interest, everything is covered clearly. These RD Sharma Solutions are not only helpful for doing homework but also great for revision before tests.
In short, RD Sharma Solutions for Class 7 Chapter 13 are a smart way to learn and master the topic of Simple Interest. They provide clear explanations, easy steps, and plenty of practice so that every student can feel confident in this important maths concept.
RD Sharma Class 7 Chapter 13 PDF includes detailed solutions, examples, and extra questions to help you master real numbers and other topics. Click here to download the RD Sharma Class 7 Chapter 13 PDF.
In this chapter, students will learn about decimals and how to perform basic operations with them. The solutions provided here are detailed and easy to follow, helping students understand each concept thoroughly.
Q1. Calculate the simple interest in the following cases:
(i) Principal = Rs 2000, Rate = 5% per year, Time = 5 years
Simple Interest = (2000 × 5 × 5) / 100 = Rs 500
(ii) Principal = Rs 500, Rate = 12.5% per year, Time = 4 years
Simple Interest = (500 × 4 × 12.5) / 100 = Rs 250
(iii) Principal = Rs 4500, Rate = 4% per year, Time = 6 months = 0.5 year
Simple Interest = (4500 × 0.5 × 4) / 100 = Rs 90
(iv) Principal = Rs 12000, Rate = 18% per year, Time = 4 months = 1/3 year
Simple Interest = (12000 × (1/3) × 18) / 100 = Rs 720
(v) Principal = Rs 1000, Rate = 10% per year, Time = 73 days = 73/365 years
Simple Interest = (1000 × (73/365) × 10) / 100 = Rs 20
Q2. Find the interest on Rs 500 kept for 4 years at 8% interest yearly. Also find the total amount received.
Simple Interest = (500 × 4 × 8) / 100 = Rs 160
Total Amount = 500 + 160 = Rs 660
Q3. Rs 400 is given on loan at 5% yearly for 2 years. Calculate the interest earned.
Simple Interest = (400 × 2 × 5) / 100 = Rs 40
Q4. Rs 400 is lent for 3 years at 6% per year. Find the interest.
Simple Interest = (400 × 3 × 6) / 100 = Rs 72
Q5. A person deposits Rs 25000 in a company offering 20% yearly interest. Find his yearly income.
Simple Interest = (25000 × 1 × 20) / 100 = Rs 5000
Q6. A man borrows Rs 8000 from a bank at 8% yearly for 4.5 years. Find the amount he needs to repay.
Time = 4.5 years = 9/2 years
Simple Interest = (8000 × (9/2) × 8) / 100 = Rs 2880
Total Amount = 8000 + 2880 = Rs 10880
Q7. Rakesh gives Rs 8000 on loan for 5 years at 15% per year. He also takes Rs 6000 on loan for 3 years at 12% per year. Find his gain or loss.
Interest earned = (8000 × 5 × 15) / 100 = Rs 6000
Interest paid = (6000 × 3 × 12) / 100 = Rs 2160
Net Gain = 6000 − 2160 = Rs 3840
Q8. Anita deposits Rs 1000 in a savings bank that gives 5% yearly interest. How much will she get after 1 year?
Simple Interest = (1000 × 1 × 5) / 100 = Rs 50
Total Amount = 1000 + 50 = Rs 1050
Q9. Nalini borrows Rs 550 from a friend at 8% yearly and returns it after 6 months. What is the total amount she pays?
Time = 6 months = 0.5 year
Simple Interest = (550 × 0.5 × 8) / 100 = Rs 22
Total Amount = 550 + 22 = Rs 572
Q10. Rohit borrows Rs 60000 from a bank at 9% yearly for 2 years. He lends the same to Rohan at 10% yearly for 2 years. How much does Rohit earn?
Interest received = (60000 × 2 × 10) / 100 = Rs 12000
Interest paid = (60000 × 2 × 9) / 100 = Rs 10800
Profit = 12000 − 10800 = Rs 1200
This chapter introduces students to the concept of simple interest, where they learn how to calculate the extra money earned or paid when money is borrowed or invested. It includes the formula for simple interest, explanation of terms like principal, rate, and time, and plenty of solved problems and exercises.
The formula for Simple Interest is:
SI = (P × R × T) / 100,
where SI = Simple Interest, P = Principal, R = Rate of Interest per annum, and T = Time in years.
RD Sharma Solutions provide clear explanations and step-by-step solutions for all the questions in the textbook. They help students understand how to apply the formula correctly and solve both direct and word problems related to simple interest.
Yes, the solutions are extremely helpful for exam preparation. They cover all types of problems asked in exams, including important examples and exercises that help students revise the topic thoroughly.
Absolutely. The RD Sharma Solutions for Chapter 13 are great for completing homework accurately and for extra practice. They build confidence by reinforcing key concepts and improving problem-solving skills.
Yes, the chapter includes several word problems that relate to real-life situations such as bank deposits, borrowing money, and interest on loans, making the concept easier to understand.
Yes, RD Sharma Solutions are available online and can also be downloaded in PDF format from various educational websites. This makes it easy for students to access them anytime, even offline.