RD Sharma Solutions for Class 7 Maths Chapter 10 Unitary Method

In Class 7, Mathematics becomes more interesting as you dive into different methods and techniques to solve problems. One of the key topics in this journey is the Unitary Method, which is covered in Chapter 10 of RD Sharma's Class 7 Maths book. The Unitary Method is a fundamental concept that helps you solve a wide range of problems related to ratios, proportions, and measurements.

But what exactly is the Unitary Method? In simple terms, it is a technique used to solve problems where we first find the value of a single unit (also known as the unitary value), and then use that to find the value of multiple units. This method is especially helpful when dealing with real-life situations, like calculating the cost of multiple items, speed, or time. It breaks down complicated problems into smaller, more manageable steps.

For example, if you know the cost of one apple and want to calculate the cost of 10 apples, the Unitary Method will help you do that easily. By first determining how much one apple costs, you can then multiply that value by 10 to get the total cost for 10 apples. This approach works the same way for other types of calculations, whether you're dealing with distance, time, or quantities.

In this chapter, you will learn how to apply the Unitary Method to a variety of problems. The RD Sharma Solutions provide detailed, step-by-step solutions to each exercise, making it easier for you to understand the process and learn the techniques to solve these problems on your own. Whether it's about calculating the cost of goods, converting units, or solving word problems, the Unitary Method will become an essential tool in your problem-solving kit.

By practicing the examples and solutions provided in this chapter, you will be able to approach different types of problems with confidence. You'll gain the ability to solve them quickly and accurately, which will help you build a strong foundation for higher-level mathematics. With a little practice, you’ll be able to apply the Unitary Method with ease, not only in exams but also in everyday life.

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Download RD Sharma Solutions for Class 7 Maths Chapter 10 Unitary Method PDF Here

RD Sharma Class 7 Chapter 10 PDF includes detailed solutions, examples, and extra questions to help you master real numbers and other topics. Click here to download the RD Sharma Class 7 Chapter 10 PDF.

Access Answers to RD Sharma Solutions for Class 7 Maths Chapter 10 Unitary Method

In this chapter, students will learn about decimals and how to perform basic operations with them. The solutions provided here are detailed and easy to follow, helping students understand each concept thoroughly.

Q1. 20 chocolates cost Rs 320. Find the cost of 35 chocolates.

Solution:

Cost of 20 chocolates = Rs 320

Cost of 1 chocolate = (320 / 20)

Therefore, cost of 35 chocolates = (320 / 20) × 35 = Rs 560

Q2. The cost of 40 meters of cloth is Rs 200. Find the cost of 50 meters of cloth.

Solution:

Cost of 40 meters = Rs 200

Cost of 1 meter = (200 / 40)

Therefore, cost of 50 meters = (200 / 40) × 50 = Rs 250

Q3. A car can cover 522 km with 36 litres of petrol. How far can it travel with 14 litres of petrol?

Solution:

Distance covered by 36 litres = 522 km

Distance covered by 1 litre = 522 / 36

Therefore, distance covered by 14 litres = (522 / 36) × 14 = 203 km

Q4. Traveling 900 km by rail costs Rs 280. What is the fare for a 360 km journey in the same class?

Solution:

Cost of traveling 900 km = Rs 280

Cost of traveling 1 km = 280 / 900

Therefore, cost of traveling 360 km = (280 / 900) × 360 = Rs 112

Q5. If 6 oil tankers are filled in 4(1/2) hours, how long will it take to fill 4 tankers?

Solution:

Time taken to fill 6 oil tankers = 4(1/2) hours = 9/2 hours

Time taken to fill 1 oil tanker = (9/2) / 6 = 9 / 12 hours

Time to fill 4 tankers = (9 / 12) × 4 = 3 hours

Q6. 3/4 of the monthly salary is Rs 600. Find the full monthly salary.

Solution:

3/4 of the salary = Rs 600

Let the full salary be x. So, (3/4) × x = 600

x = 600 × (4 / 3) = 800

Therefore, the full salary is Rs 800

Q7. The cost of 32 tables is Rs 23,520. How many tables can be bought for Rs 51,450?

Solution:

Cost of 32 tables = Rs 23,520

Cost of 1 table = 23,520 / 32

Therefore, number of tables bought for Rs 51,450 = (23,520 / 32) × 51,450 = 70 tables

Q8.The yield of wheat from 6 hectares is 280 quintals. How many hectares are needed for a yield of 225 quintals?

Solution:

Number of hectares for 280 quintals = 6 hectares

Hectares for 1 quintal = 6 / 280 hectares

Therefore, hectares for 225 quintals = (6 / 280) × 225 = 4 23/28 hectares

Q9.15 postcards cost Rs 2.25. What is the cost of 36 postcards? How many postcards can be bought for Rs 45?

Solution:

Cost of 15 postcards = Rs 2.25

Cost of 1 postcard = 2.25 / 15

Therefore, the cost of 36 postcards = (2.25 / 15) × 36 = Rs 5.40

Number of postcards bought for Rs 2.25 = 15

Number of postcards bought for Rs 1 = 15 / 2.25

Therefore, number of postcards bought for Rs 45 = (15 / 2.25) × 45 = 300 postcards

Q10. A 75 km rail journey costs Rs 215. What is the cost of a 120 km journey?

Solution:

Cost of 75 km journey = Rs 215

Cost of 1 km journey = 215 / 75

Therefore, cost of 120 km journey = (215 / 75) × 120 = Rs 344

Q11. If the sales tax on a Rs 60 purchase is Rs 4.20, what is the sales tax on a purchase worth Rs 150?

Solution:

Sales tax on Rs 60 purchase = Rs 4.20

Sales tax for Rs 1 purchase = 4.20 / 60

Therefore, sales tax on Rs 150 purchase = (4.20 / 60) × 150 = Rs 10.50

Q12. 52 packets of 12 pencils each cost Rs 499.20. What is the cost of 65 packets of 10 pencils each?

Solution:

Number of pencils in 52 packets = 52 × 12 = 624 pencils

Cost of 624 pencils = Rs 499.20

Cost of 1 pencil = 499.20 / 624

Number of pencils in 65 packets of 10 pencils each = 65 × 10 = 650 pencils

Therefore, the cost of 650 pencils = (499.20 / 624) × 650 = Rs 520