25ml of 3M HCl are mixed with 75ml of 4M HCl. If the volumes are addictives, the molarity of the final solution will be

A
4M
B
3.75M
C
4.25M
D
3.5M

Solution:

$\begin{array}{l} M_{3} V_{3} = M_{1} V_{1} + M_{2} V_{2}, M_{3} = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{3}} = \frac{3 \times 25 + 4 \times 75}{25 + 75} = 3.75 M \end{array}$

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