29.2% w/w HCl stock solution has a density of 1.25gm/ml. The mol.wt of HCl is 36.5g/mole. The volume of stock solution required to prepare a 200ml solution of 0.4M HCl is ________. - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

Solution:

$\begin{array}{l} M = \frac{10 \times p \times d}{GMW of HCl} = \frac{29 .2 \times 1 .25 \times 10}{36 .5} = 10 M \\ M_{1} V_{1} = M_{2} V_{2} \Rightarrow 10 \times V_{1} = 200 \times 0 .4 \\ V_{1} = \frac{200 \times 0 .4}{10} = 8 mL \end{array}$

Solution:

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