6g of non volatile solute is dissolved in 90g of water, such that the lowering of vapour pressure is 2% . The molecular weight of solute is

  1. A

    65

  2. B

    92

  3. C

    60

  4. D

    80

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    Solution:

    Wt of non volatile solute W1  = 6g

    Wt of solvent (Water)=W2=90g

    GMW of solute=M1=?

    GMW of solvent H2O=M2=18g

    R.L.V.P=pp0=2100  

     According to Raoults law  

     pp0=W1M1×M2W2 

    2100=6M1×1890 

     M1=6×182×90×100; M1=60

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