A 0.101 M solution of ${\mathrm{Ba}}_3{\left({\mathrm{PO}}_4\right)}_2$ is isotonic with 0.004 M glucose solution. The degree of dissociation and van't Hoff factor of ${\mathrm{Ba}}_3{\left({\mathrm{PO}}_4\right)}_2$, respectively, are

$$\begin{gathered} i=\frac{\mathrm{\Pi }}{(\mathrm{\Pi }{)}_0} \\ =\frac{\left(0.004\mathrm{M}\right)RT}{\left(0.001\mathrm{M}\right)RT} \\ =4; \\ \alpha =\frac{i-1}{v-1}=\frac{4-1}{5-1}=\frac{3}{4}=0.75 \end{gathered}$$

Thus, the degree of dissociation and van't Hoff factor of ${\mathrm{Ba}}_3{\left({\mathrm{PO}}_4\right)}_2$, respectively, are 4 and 0.75.