Solution:
Amount of AgCl obtained,
Let x be the mass of , then
Amount of and Amount of
Hence,
Solving for x, we get
A 0.50 g sample containing only anhydrous ( molar mass: ) and (molar mass: yielded of (molar mass: ). The mass of in the sample is
Amount of AgCl obtained,
Let x be the mass of , then
Amount of and Amount of
Hence,
Solving for x, we get