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Q.

A certain quantity of electricity is passed through an aqueous solution of ${AgNO}_{3}$ and ${CuSO}_{4}$ solution in series. If the mass of Ag deposited is 1.08 g, the mass of copper deposited will be

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a

$0.3175 g$

b

$6.35 g$

c

$1.270 g$

d

$0.635 g$

answer is C.

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Detailed Solution

Amount of electricity passed $= \frac{1.08 g}{108 g {mol}^{- 1}} = 0.01 mol$

Amount of copper deposited $= (\frac{63.5 g {mol}^{- 1}}{2}) (0.01 mol) = 0.3175 g$

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