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A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of the same solution is studied using $NaCl,$ ${BaCl}_{2}$ and ${AlCl}_{3}$ solutions. Their coagulating power should be :

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\begin{aligned} NaCl > {BaCl}_{2} > {AlCl}_{3} \end{aligned}

{BaCl}_{2} > {AlCl}_{3} > {NaCl}^{}

\begin{aligned} {AlCl}_{3} > {BaCl}_{2} > NaCl \end{aligned}

{BaCl}_{2} > NaCl > {AlCl}_{3}

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detailed solution

Correct option is C

When colloidal solution is exposed to electrical field, coagulating power should be in the order of ${AlCl}_{3} > {BaCl}_{2} > NaCl$ as their valency is rising.

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A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of the same solution is studied using NaCl, BaCl2 and AlCl3 solutions. Their coagulating power should be :