A coloured solution of an inorganic salt reacts with potassium thiocyanate to give first a black precipitate , which slowly turns white. The salt solution also gives black precipitate with $H_{2} S$ gas in slightly acidic medium. The black precipitate dissolves in potassium cyanide forming a colourless solution. The basic radical present in the inorganic salt is :

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none of these

${Cu}^{2 +}$

${Bi}^{3 +}$

${Hg}^{2 +}$

answer is B.

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Detailed Solution

${Cu}^{2 +} \overset{{SCN}^{-}}{⟶} Cu ({SCN}_{2} ↓⟶ CuSCN ↓ + ({SCN}_{2} ↑ (Black ppt .) (white) ↓ H_{2} S, H^{+} CuS ↓ \to_{excess}^{KCN} {[Cu (CN)_{4}]}_{3} (Black)$

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