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A compound X of the formula $C_{2} H_{6} O,$ on reaction with Na metal gave Y, X also reacts with ${PCl}_{5}$ to give Z. The product obtained in the reaction between Y and Z is

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a

{CH}_{3} CHO

b

{CH}_{3} {COCH}_{3}

c

{CH}_{3} {COOC}_{2} H_{5}

d

C_{2} H_{5} {OC}_{2} H_{5}

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detailed solution

Correct option is D

The compound X, Y and Z are ethanol (C₂H₅OH), sodium ethoxide (C₂H₅ONa) and ethyl chloride (C₂H₅Cl) respectively.

Ethanol reacts with Na metal to form sodium ethoxide.

$\underset{X}{C_{2} H_{5} OH} + Na \to \underset{Y}{C_{2} H_{5} ONa} + \frac{1}{2} H_{2}$

Ethanol also reacts with PCl₅ to give ethyl chloride.

$\underset{X}{C_{2} H_{5} OH} + {PCl}_{5} \to \underset{Z}{C_{2} H_{5} Cl}$

Diethyl ether forms when sodium ethoxide (Y) and ethyl chloride (Z) react with each other.

$\underset{Y}{C_{2} H_{5} ONa} + \underset{Z}{C_{2} H_{5} Cl} \to C_{2} H_{5} {OC}_{2} H_{5} + NaCl$

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