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A first-order reaction which is 30% complete in 30 minutes has a half-life period of

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Correct option is B

$\begin{array}{l} k = \frac{2 .303}{t} \log \frac{a}{a - x} \\ \frac{0 .693}{t_{1 / 2}} = \frac{2 .303}{30} \log \frac{100}{100 - 30} \\ ∴ t_{1 / 2} = 58 .2 \min . \end{array}$

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