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Q.

A solid XY kept in an evacuated sealed container undergoes decomposition to form a mixture of gases X and Y at temperature T. The equilibrium pressure is 10 bar in this vessel. KP for this reaction is:

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a

100

b

25

c

10

d

5

answer is A.

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Detailed Solution

XY(s)⇌X(g)+Y(g) Equilibrium pressure =pX+pY=10bar

Since pX=pY we have pX=pY=5 bar . The value of equilibrium constant will be Kp=pXpY=(5bar)2=25bar2

 

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