A solution is 0.1 Min formic acid Ka=2.0×10−4M. and 0.1 Min hydrofluoric acid Ka=8.0×10−4M. Its pH will be about

A solution is 0.1 Min formic acid $(K_{a} = 2.0 \times 10^{- 4} M)$ . and 0.1 Min hydrofluoric acid $(K_{a} = 8.0 \times 10^{- 4} M)$ . Its pH will be about

A
2.0
B
2.5
C
3.0
D
4.0

Solution:

${[H_{3} O^{+}] = (K_{1} c_{1} + K_{2} c_{2}) = [(2.0 \times 10^{- 4} M) (0.1 M) + (8.0 \times 10^{- 4} M)) (0.1 M)]}^{1 / 2} = 1.0 \times 10^{- 2} M pH = - \log (1.0 \times 10^{- 2}) = 2.0$

Related content

Distance Speed Time Formula

Refractive Index Formula

Mass Formula

Electric Current Formula

Ohm’s Law Formula

Wavelength Formula

Electric Power Formula

Resistivity Formula

Weight Formula

Linear Momentum Formula