A solution of glucose (C₆H₁₂O_{6 )} is 18% by mass. The mole fraction of glucose will be

Molar mass of ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6$  , $M_2=180\mathrm{g}{\mathrm{mol}}^{-1}$

Mass of glucose in the 100 g solution  m₂ = 18 g

Amount of glucose in 100 g solution $n_2=\frac{m_2}{M_1}=\frac{10\mathrm{g}}{180\mathrm{g}{\mathrm{mol}}^{-1}}=0.1\mathrm{mol}$

Mass of water in 100 g solution, $m_1=82\mathrm{g}$

Amount of water in 100 g solution $n_1=\frac{m_1}{M_1}=\frac{8\mathrm{\angle }\mathrm{g}}{18\mathrm{g}{\mathrm{mol}}^{-1}}=4.56\mathrm{mol}$

Mole fraction of glucose, $x_2=\frac{n_2}{n_1+n_2}=\frac{0.1\mathrm{mol}}{(4.56+0.1)\mathrm{mol}}=0.0214$