A+ 2B + 3C⇌ AB2C3 . Reaction of 6.0 g of atoms of B, and 0.036 mol of C yields 4.8 g of compound AB2C3 . If the atomic masses of A and C are 60 and 80 amu, respectively, the atomic mass B of is (Avogadro constant= 6 x 1023 mol-1)

A+ 2B + 3C AB2C3 . Reaction of 6.0 g of atoms of B, and 0.036 mol of C yields 4.8 g of compound AB2C3 . If the atomic masses of A and C are 60 and 80 amu, respectively, the atomic mass B of is (Avogadro constant= 6 x 1023 mol-1)

  1. A

    70 amu

  2. B

    60 amu

  3. C

    50 amu 

  4. D

    40 amu

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    Solution:

    The given data are:

    A6.0 g +2B6.0 x 1023atoms +3C0.036 molAB2C34.8 g

    =660mol 1mol

    Maximum extent of reaction 0.1mol 0.5mol 0.012mol

    The limiting reagent is the atomC. The amount of AB2C3 formed will also be 0.012 mol. Mass of AB2C3 formed is 4.8 g. Hence

    (0.012×60+(0.024mol)MR+036×80)g=4.8g

    This gives  MB=50gmol1 Thus, atomic mass of B is 50 amu .

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