A+ 2B + 3C⇌ AB2C3 . Reaction of 6.0 g of atoms of B, and 0.036 mol of C yields 4.8 g of compound AB2C3 . If the atomic masses of A and C are 60 and 80 amu, respectively, the atomic mass B of is (Avogadro constant= 6 x 1023 mol-1)

# . Reaction of of atoms of $\mathrm{B}$, and  of $\mathrm{C}$ yields  of compound . If the atomic masses of $\mathrm{A}$ and $\mathrm{C}$ are $60$ and , respectively, the atomic mass $\mathrm{B}$ of is

1. A

70 amu

2. B

60 amu

3. C

50 amu

4. D

40 amu

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### Solution:

The given data are:

Maximum extent of reaction

The limiting reagent is the atom$\mathrm{C}$. The amount of ${\mathrm{AB}}_{2}{\mathrm{C}}_{3}$ formed will also be 0.012 mol. Mass of ${\mathrm{AB}}_{2}{\mathrm{C}}_{3}$ formed is . Hence

$\left(0.012×60+\left(0.024mol\right){M}_{R}+036×80\right)g\mathit{=}\mathit{4}\mathit{.8}g$

This gives  ${M}_{\mathrm{B}}=50\mathrm{g}{\mathrm{mol}}^{-1}$ Thus, atomic mass of B is .

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