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Acetyl bromide reacts with excess of  CH3MgI followed by treatment with a saturated solution of NH4Cl gives

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a
acetone
b
acetamide
c
2-methyl-2-propanol
d
acetyl iodide

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detailed solution

Correct option is C

The reaction is

 

The tertiary alcohol produced when acetyl bromide combines with excess CH3 MglI and then is treated with a saturated solution of NH4Cl is 2-methyl-2-propanol, according to the supplied option.

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