Acetyl bromide reacts with excess of  CH3MgI followed by treatment with a saturated solution of NH4Cl gives

  1. A

    acetone

  2. B

    acetamide

  3. C

    2-methyl-2-propanol

  4. D

    acetyl iodide

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    Solution:

    The reaction is

     

    The tertiary alcohol produced when acetyl bromide combines with excess CH3 MglI and then is treated with a saturated solution of NH4Cl is 2-methyl-2-propanol, according to the supplied option.

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