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Questions

An element has electronic configuration as $1 s^{2}, 2 s^{2}$ $2 p^{6}, 3 s^{2} 3 p^{6}, 4 s^{2}, 3 d^{7}$ .
The correct statement regarding element is :

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a

Element must be

Co

b

Element belongs to group number '9' according to the long form of periodic table

c

Maximum number of electrons in element having

m = + 1

are 6

d

Element has magnetic moment

\sqrt{15} BM

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detailed solution

Correct option is A

The electronic configuration of cobalt (Co) is $1 s^{2}, 2 s^{2}$ , $2 p^{6}, 3 s^{2} 3 p^{6}, 4 s^{2}, 3 d^{7}$ . Cobalt lies in the group 9, The maximum number of electron is 6. Cobalt has 3 unpaired electrons. The magnetic moment of the compound is,

$μ = n (n + 2)$

$μ = 3 (3 + 2)$

$μ = 15 B M$

Hence, all the statement about the cobalt is correct.

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