# An element z has an electronic configuration : $n{s}^{2}n{p}^{6}$$\left(n-1\right){d}^{10}\left(n-2\right){f}^{14}$. Which value of n is not possible

1. A

6

2. B

3

3. C

5

4. D

Both (b) and (c)

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### Solution:

For n=6,

$6{s}^{2},6{p}^{6},5{d}^{10},4{f}^{\mathrm{\prime }4}$

This is a possible electronic configuration.

For n=3,

$\begin{array}{l}\mathit{⇒}\mathit{3}{\mathit{s}}^{\mathit{2}}\mathit{,}\mathit{3}{\mathit{p}}^{\mathit{6}}\mathit{,}\mathit{\left(}\mathit{3}\mathit{-}\mathit{1}\mathit{\right)}{\mathit{d}}^{\mathit{10}}\mathit{\left(}\mathit{3}\mathit{-}\mathit{2}\mathit{\right)}{\mathit{f}}^{\mathit{14}}\\ \mathit{⇒}\mathit{3}{\mathit{s}}^{\mathit{2}}\mathit{,}\mathit{3}{\mathit{p}}^{\mathit{6}}\mathit{,}\mathit{2}{\mathit{d}}^{\mathit{10}}\mathit{,}\mathit{1}{\mathit{f}}^{\mathit{14}}\end{array}$

This is not possible.

For n=5,

$5{s}^{\mathit{2}},s{p}^{\mathit{6}}4{d}^{\mathit{10}}3{f}^{\mathit{14}}$

This is not possible.

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