An organic compound A upon reacting with ${NH}_{3}$ gives B. On heating B gives C. The compound C in presence of $KOH$ reacts with ${Br}_{2}$ to give ${CH}_{3} {CH}_{2} {NH}_{2}$ . The compound A is

A
${CH}_{3} COOH$
B
${CH}_{3} {CH}_{2} {CH}_{2} COOH$
C
${CH}_{3} - \underset{|}{C} H - COOH {CH}_{3}$
D
${CH}_{3} {CH}_{2} COOH$

Solution:

We have

So the compound A is,

${CH}_{3} {CH}_{2} COOH$

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