An organic compound undergoes first order decomposition. The time taken for its decomposition to 18  and  110 of its intial concentration are  t18 and t110  respectively. What is the value of t18t110×10

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    Solution:

    Y is 12

    K=2.303t18logaa8=2.303t18log8 ---------(1)
    K=2.303t18loga(a/10)=2.303t18log10  -----------(2)
    Eq1Eq21=t18t110×log8log10 t18t110=3log2=3×0.3010 t18t110×10=3×0.3010×10=9

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