Assertion (A): Chlorine gas disproportionate in hot and conc. $N a O H$ solution.

Reason (R): $N a C l$ and $N a O C l$ and are formed in the above reaction.

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Both (A) and (R) are true and (R) is the correct explanation of (A).

(A) is true but (R) is false.

(A) is false and (R) is true.

Both (A) and (R) are true but (R) is not the correct explanation of (A).

answer is C.

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Detailed Solution

Concept: In redox chemistry, the disproportion reaction is the process by which one chemical with an intermediate oxidation state splits into two compounds, one of which gains a higher oxidation state and the other a lower one.
When concentrated NaOH react with Chlorine:

The chlorine oxidation state in the reactant

is 0 and in products is: of chloride ion is -1

and that of chlorate ion is +5

. Therefore, it's a disproportionate reaction. Thereby, the assertion given is true.
As we can see, the products of the reaction are not