Assertion (A): Chlorine gas disproportionate in hot and conc. NaOH solution. Reason (R): NaCl and NaOCl and are formed in the above reaction. - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
Both (A) and (R) are true and (R) is the correct explanation of (A).
B
Both (A) and (R) are true but (R) is not the correct explanation of (A).
C
(A) is true but (R) is false.
D
(A) is false and (R) is true.

Solution:

Concept: In redox chemistry, the disproportion reaction is the process by which one chemical with an intermediate oxidation state splits into two compounds, one of which gains a higher oxidation state and the other a lower one.
When concentrated NaOH react with Chlorine:

The chlorine oxidation state in the reactant

is 0 and in products is: of chloride ion is -1

and that of chlorate ion is +5

. Therefore, it's a disproportionate reaction. Thereby, the assertion given is true.
As we can see, the products of the reaction are not

N a C l

and

N a O C l

. Thus, the reason is wrong.
Hence, the correct answer is option 3.

Assertion (A): Chlorine gas disproportionate in hot and conc. $N a O H$ solution.

Reason (R): $N a C l$ and $N a O C l$ and are formed in the above reaction.

Solution:

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