Assuming 100% ionization, the increasing order of the freezing point of the solution will be

Assuming 100% ionization, the increasing order of the freezing point of the solution will be

  1. A

    0.10 mol kg-1 Ba3PO42<0.10 mol kg-1Na2SO4<0.10 mol kg-1KCl

  2. B

    0.10 mol kg-1KCl<0.10 mol kg-1Na2SO4<0.10 mol kg-1Ba3PO42

  3. C

    0.10 mol kg-1Na2SO4<0.10 mol kg1Ba3PO42<0.10 mol kg1KCl

  4. D

    0.10 mol kg-1KCl<0.10 mol kg-1Ba3PO42<0.10 mol kg-1Na2SO4

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    Solution:

    Assuming complete dissociation -ΔTfBa3PO42>-ΔTfNa2SO4>-ΔTfKCl

    Hence TfBa3PO42<TfNa2SO4<TfKCl

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