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At temperature T, the average kinetic energy of any particle is $\frac{3}{2} kT$ . The de Broghie wavelength follows the order :

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Visible photon > Thermal electron > Thermal neutron

Thermal proton > Thermal electron > visible photon

Visible photon > Thermal neutron > Thermal electron

Thermal proton > Visible photon > Thermal electron

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detailed solution

Correct option is A

It is known that;

$λ \propto \frac{1}{\sqrt{m}}$

Hence, Visible photon > Thermal electron > Thermal neutron.

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At temperature T, the average kinetic energy of any particle is 32kT. The de Broghie wavelength follows the order :