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Q.

At $100^{\circ} C$ and 1atm, if the density of liquid water is $1.0 g c m^{- 3}$ and that of water vapour is $0.0006 g {cm}^{- 3}$ , then the volume occupied by water molecules in 1 litre of steam at this temperature is :

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a

$6 {cm}^{3}$

b

$60 {cm}^{3}$

c

$0.6 {cm}^{3}$

d

$0.06 {cm}^{3}$

answer is C.

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Detailed Solution

Mass of steam $= 1000 \times 0.0006 = 0.6 g$ $∴ Volume of water molecules = \frac{0.6}{1} = 0.6 {cm}^{3}$

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At 100∘C and 1atm, if the density of liquid water is 1.0 g cm-3 and that of water vapour is 0.0006 gcm−3, then the volume occupied by water molecules in 1 litre of steam at this temperature is :